ocr: Solving for t2c. we t2c = '2c =t2-1- 300 initial Since this guess (Po) equation at its still value; contains this P, is the used quantity we are seeking, we begin by makng an together with the known values oftz and to find a: first estimate of t2c. which we may call 2c1 Next we let P1 = 12c1:'1 and repeat the evaluation of t2c,to gett2c2i then P2=t2c2-1 This process is repeated until the iitterence Pn - Pn-1 is less than 1min= 0.02 h, the possible emor of our time observation. This process is easily done by computer (and in this case may even be done using a. hand calculator). Write a computer ...
