Labels:text | font | screenshot OCR: Solving for 12c, we t2c =12c =12 -11 -360 BP. Since this equation still contains P, the quantity we are seeking, we begin by making an initial guess (Pg) at its value; this is used together with the known values of t, and B to find a first estimate of t20, which we may call 12c] .. Next we let P1 = 12c1 - 11 and repeat the evaluation of t2c , to get 12c2; then P2 = 12c2 - 11 . This process is repeated until the difference Pn - Pn-1 is less than 1 min = 0.02 h, the possible error of our time observation. This process is easily done by computer (and in this case may even be done using a hand calculator). Write a computer program to perform this iteration. Solution: We display a program written in BASIC.
